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42x^2=378
We move all terms to the left:
42x^2-(378)=0
a = 42; b = 0; c = -378;
Δ = b2-4ac
Δ = 02-4·42·(-378)
Δ = 63504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{63504}=252$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-252}{2*42}=\frac{-252}{84} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+252}{2*42}=\frac{252}{84} =3 $
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